0.16x^2=0.08x+0.01=0.16

Solution for 0.16x^2=0.08x+0.01=0.16 equation:

0.16x^2=0.08x+0.01=0.16

We move all terms to the left:

0.16x^2-(0.08x+0.01)=0

We get rid of parentheses

0.16x^2-0.08x-0.01=0

a = 0.16; b = -0.08; c = -0.01;
Δ = b2-4ac
Δ = -0.082-4·0.16·(-0.01)
Δ = 0.0128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.08)-\sqrt{0.0128}}{2*0.16}=\frac{0.08-\sqrt{0.0128}}{0.32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.08)+\sqrt{0.0128}}{2*0.16}=\frac{0.08+\sqrt{0.0128}}{0.32}
$